regex in python to obtain only the string in python
import re
print(" ".join(re.findall("[a-zA-Z]","your string")))
regex in python to obtain only the string in python
import re
print(" ".join(re.findall("[a-zA-Z]","your string")))
Using the Python string below to perform a search using a regular expression that you create. search_string=’’’This is a string to search for a regular expression like regular expression or regular-expression or regular:expression or regular&expression’’’
match1 = re.findall(pattern, search_string)
if match1 != None:
print(pattern + 'matched')
else:
print(pattern + 'did not match')
python .findall
## Search for pattern 'bb' in string 'aabbcc'.
## All of the pattern must match, but it may appear anywhere.
## On success, match.group() is matched text.
match = re.search(r'bb', 'aabbcc') # found, match.group() == "bb"
match = re.search(r'cd', 'aabbcc') # not found, match == None
## . = any char but n
match = re.search(r'...c', 'aabbcc') # found, match.group() == "abbc"
## d = digit char, w = word char
match = re.search(r'ddd', 'p123g') # found, match.group() == "123"
match = re.search(r'www', '@@abcd!!') # found, match.group() == "abc"
py string find regex pos
import re
re.search('o{3}', 'Python is slooow!').start() # 12
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