how to print the address of a pointer in c
int a = 42;
printf("%pn", (void *) &a);how to print the address of a pointer in c
int a = 42;
printf("%pn", (void *) &a);how to print value of pointer in c
#include <stdio.h>
#include <stdlib.h>
void pointerFuncA(int* iptr){
/*Print the value pointed to by iptr*/
printf("Value: %dn", *iptr );
/*Print the address pointed to by iptr*/
printf("Value: %pn", iptr );
/*Print the address of iptr itself*/
printf("Value: %pn", &iptr );
}
int main(){
int i = 1234; //Create a variable to get the address of
int* foo = &i; //Get the address of the variable named i and pass it to the integer pointer named foo
pointerFuncA(foo); //Pass foo to the function. See I removed void here because we are not declaring a function, but calling it.
return 0;
}c printing char pointer
#include <stdio.h>
int main()
{
char * str = "Hello";
printf("%sn", str);
return 0;
}Copyright © 2021 Codeinu
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