array length c
int prices[5] = { 1, 2, 3, 4, 5 };
int size = sizeof prices / sizeof prices[0];
printf("%u", size); /* 5 */array length c
int prices[5] = { 1, 2, 3, 4, 5 };
int size = sizeof prices / sizeof prices[0];
printf("%u", size); /* 5 */n no of array in c using malloc
#include <stdio.h>
int main()
{
printf("nnttStudytonight - Best place to learnnnn");
int n, i, *ptr, sum = 0;
printf("nnEnter number of elements: ");
scanf("%d", &n);
// dynamic memory allocation using malloc()
ptr = (int *) malloc(n*sizeof(int));
if(ptr == NULL) // if empty array
{
printf("nnError! Memory not allocatedn");
return 0; // end of program
}
printf("nnEnter elements of array: nn");
for(i = 0; i < n; i++)
{
// storing elements at contiguous memory locations
scanf("%d", ptr+i);
sum = sum + *(ptr + i);
}
// printing the array elements using pointer to the location
printf("nnThe elements of the array are: ");
for(i = 0; i < n; i++)
{
printf("%d ",ptr[i]); // ptr[i] is same as *(ptr + i)
}
/*
freeing memory of ptr allocated by malloc
using the free() method
*/
free(ptr);
printf("nntttCoding is Fun !nnn");
return 0;
}Copyright © 2021 Codeinu
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