Answers for "c++ return 2d array"

how to return 2d array from function c++

#include <cstdio>

    // Returns a pointer to a newly created 2d array the array2D has size [height x width]

    int** create2DArray(unsigned height, unsigned width)
    {
      int** array2D = 0;
      array2D = new int*[height];
    
      for (int h = 0; h < height; h++)
      {
            array2D[h] = new int[width];
    
            for (int w = 0; w < width; w++)
            {
                  // fill in some initial values
                  // (filling in zeros would be more logic, but this is just for the example)
                  array2D[h][w] = w + width * h;
            }
      }
    
      return array2D;
    }
    
    int main()
    {
      printf("Creating a 2D array2Dn");
      printf("n");
    
      int height = 15;
      int width = 10;
      int** my2DArray = create2DArray(height, width);
      printf("Array sized [%i,%i] created.nn", height, width);
    
      // print contents of the array2D
      printf("Array contents: n");
    
      for (int h = 0; h < height; h++)
      {
            for (int w = 0; w < width; w++)
            {
                  printf("%i,", my2DArray[h][w]);
            }
            printf("n");
      }
    
          // important: clean up memory
          printf("n");
          printf("Cleaning up memory...n");
          for (int h = 0; h < height; h++) // loop variable wasn't declared
          {
            delete [] my2DArray[h];
          }
          delete [] my2DArray;
          my2DArray = 0;
          printf("Ready.n");
    
      return 0;
    }

c++ code to write 2d array

#include <iostream>
using namespace std;
int main(){
	int n,m;
	int a[n][m];
	cin >> n >>m;
	for ( int i=0; i<n; i++){
		for (int j=0; j<m; j++){
			cin >> a[i][j];
		}
	}
	
	for ( int x=0; x<n; x++){
		for (int y=0; y<m; y++){
			cout << "a[" << x << "][" << y << "]: ";
			cout << a[x][y] << endl;
		}
	}
	return 0;
}