Answers for "calloc and malloc"

how to dynamically allocate array size in c

// declare a pointer variable to point to allocated heap space
int    *p_array;
double *d_array;

// call malloc to allocate that appropriate number of bytes for the array

p_array = (int *)malloc(sizeof(int)*50);      // allocate 50 ints
d_array = (int *)malloc(sizeof(double)*100);  // allocate 100 doubles


// use [] notation to access array buckets 
// (THIS IS THE PREFERED WAY TO DO IT)
for(i=0; i < 50; i++) {
  p_array[i] = 0;
}

// you can use pointer arithmetic (but in general don't)
double *dptr = d_array;    // the value of d_array is equivalent to &(d_array[0])
for(i=0; i < 50; i++) {
  *dptr = 0;
  dptr++;
}

malloc in c

#include <stdlib.h>

void *malloc(size_t size);

void exemple(void)
{
  char *string;
  
  string = malloc(sizeof(char) * 5);
  if (string == NULL)
    return;
  string[0] = 'H';
  string[1] = 'e';
  string[2] = 'y';
  string[3] = '!';
  string[4] = '';
  printf("%sn", string);
  free(string);
}

/// output : "Hey!"

malloc() in c and c++

/* malloc example: random string generator*/
#include <stdio.h>      /* printf, scanf, NULL */
#include <stdlib.h>     /* malloc, free, rand */

int main ()
{
  int i,n;
  char * buffer;

  printf ("How long do you want the string? ");
  scanf ("%d", &i);

  buffer = (char*) malloc (i+1);
  if (buffer==NULL) exit (1);

  for (n=0; n<i; n++)
    buffer[n]=rand()%26+'a';
  buffer[i]='';

  printf ("Random string: %sn",buffer);
  free (buffer);

  return 0;
}

Malloc

ptr = malloc(size); //You dont need to cast