Answers for "check whether a number is palindrome or not"

check if a string is palindrome cpp

// Check whether the string is a palindrome or not.
#include <bits/stdc++.h>

using namespace std;

int main(){
    string s;
    cin >> s;
    
    int l = 0;
    int h = s.length()-1;

    while(h > l){
        if(s[l++] != s[h--]){
            cout << "Not a palindrome" << endl;
            return 0;
        }
    }
    cout << "Is a palindrome" << endl;
    return 0;

}

check a string is palindrome or not

#include <stdio.h>
#include <string.h>
int main()
{

     char str[80];
     int length;
     printf("nEnter a string to check if it's a palindrome: ");
     scanf("%s", str);     // string input
     length = strlen(str); // finding the string length
     int i, j, count;
     for (i = 0, j = length - 1, count = 0; i < length; i++, j--)
     {
          // matching string first character with the string last character
          if (str[i] == str[j])
          {
               count++; // if character match, increasing count by one.
          }
     }
     if (count == length) // if count == length, then the string is a palindrome.
     {
          printf("'%s' is a palindrome.n", str);
     }
     else // otherwise the string is not a palindrome.
     {
          printf("'%s' is not a palindrome.n", str);
     }
     return 0;
}

determine whether integer is a palindrome

public class Solution {
    public bool IsPalindrome(int x) {
        if(x < 0 || (x % 10 == 0 && x != 0)) {
            return false;
        }

        int revertedNumber = 0;
        while(x > revertedNumber) {
            revertedNumber = revertedNumber * 10 + x % 10;
            x /= 10;
        }

        return x == revertedNumber || x == revertedNumber/10;
    }
}

check palindrome

bool isPlaindrome(string s)
	{
	   int i=0;
	   int j=s.length()-1;
	   while(i<j)
	   {
	       if(s[i]==s[j])
	       {i++;
	   j--;}
	   else break;
	   }
	   if (i==j || i>j) return 1;
	   else return 0;
	}