Answers for "cycle detection in undirected graphs c++"

C++
1

detect cycle in an undirected graph c++

// A C++ Program to detect
// cycle in an undirected graph
#include<iostream>
#include <list>
#include <limits.h>
using namespace std;
 
// Class for an undirected graph
class Graph
{
     
    // No. of vertices
    int V;  
   
    // Pointer to an array
    // containing adjacency lists
    list<int> *adj; 
    bool isCyclicUtil(int v, bool visited[],
                              int parent);
public:
   
    // Constructor
    Graph(int V);  
   
    // To add an edge to graph
    void addEdge(int v, int w);
   
    // Returns true if there is a cycle
    bool isCyclic(); 
};
 
Graph::Graph(int V)
{
    this->V = V;
    adj = new list<int>[V];
}
 
void Graph::addEdge(int v, int w)
{
     
    // Add w to v’s list.
    adj[v].push_back(w);
   
    // Add v to w’s list.
    adj[w].push_back(v);
}
 
// A recursive function that
// uses visited[] and parent to detect
// cycle in subgraph reachable
// from vertex v.
bool Graph::isCyclicUtil(int v,
                bool visited[], int parent)
{
     
    // Mark the current node as visited
    visited[v] = true;
 
    // Recur for all the vertices
    // adjacent to this vertex
    list<int>::iterator i;
    for (i = adj[v].begin(); i !=
                       adj[v].end(); ++i)
    {
         
        // If an adjacent vertex is not visited,
        //then recur for that adjacent
        if (!visited[*i])
        {
           if (isCyclicUtil(*i, visited, v))
              return true;
        }
 
        // If an adjacent vertex is visited and
        // is not parent of current vertex,
        // then there exists a cycle in the graph.
        else if (*i != parent)
           return true;
    }
    return false;
}
 
// Returns true if the graph contains
// a cycle, else false.
bool Graph::isCyclic()
{
     
    // Mark all the vertices as not
    // visited and not part of recursion
    // stack
    bool *visited = new bool[V];
    for (int i = 0; i < V; i++)
        visited[i] = false;
 
    // Call the recursive helper
    // function to detect cycle in different
    // DFS trees
    for (int u = 0; u < V; u++)
    {
       
        // Don't recur for u if
        // it is already visited
        if (!visited[u])
          if (isCyclicUtil(u, visited, -1))
             return true;
    }
    return false;
}
 
// Driver program to test above functions
int main()
{
    Graph g1(5);
    g1.addEdge(1, 0);
    g1.addEdge(0, 2);
    g1.addEdge(2, 1);
    g1.addEdge(0, 3);
    g1.addEdge(3, 4);
    g1.isCyclic()?
       cout << "Graph contains cyclen":
       cout << "Graph doesn't contain cyclen";
 
    Graph g2(3);
    g2.addEdge(0, 1);
    g2.addEdge(1, 2);
    g2.isCyclic()?
       cout << "Graph contains cyclen":
       cout << "Graph doesn't contain cyclen";
 
    return 0;
}
Posted by: Guest on June-27-2021

Browse Popular Code Answers by Language