Answers for "big integer implementation c++"

bigint c++

//Bigint.hpp class
#ifndef BIGINT_HPP
#define BIGINT_HPP

#define BASE 10

#include <iostream>
#include <list>
#include"Command.hpp"
class Bigint {
public:
  Bigint() = default;  // Construct expect no arg 
  Bigint(const Bigint&) = default; // Copy constructor 
  Bigint(Bigint&&) = default; // Move constructor
  Bigint& operator=(const Bigint&) = default; // Copy assignment 
  Bigint& operator=(Bigint&&) = default; // Move assignment 
  ~Bigint(); // Destructort 
  Bigint(std::list<unsigned char>B);
  // Accessors methods ########################################################################
  bool is_zero()const;

  bool is_negative() const;

  // Friends ####################################################################################
  friend Bigint operator+(const Bigint& a, const Bigint& b);
  friend Bigint operator-(const Bigint& a, const Bigint& b);
  friend Bigint operator*(const Bigint& a, const Bigint& b);

  friend std::ostream& operator<<(std::ostream& out, const Bigint& i);
  friend std::istream& operator>>(std::istream& in, Bigint& i);
  friend Bigint minus_operator_cases(const Bigint& a, const Bigint& b);
private:
  //! Determine whether the integer is negative.
  bool m_is_negative = false;

  //! A linked list of digits.
  std::list<unsigned char> m_digits;
};

Bigint operator+(const Bigint& a, const Bigint& b);
Bigint operator-(const Bigint& a, const Bigint& b);
Bigint operator*(const Bigint& a, const Bigint& b);
std::ostream& operator<<(std::ostream& out, const Bigint& i);
std::istream& operator>>(std::istream& in, Bigint& i);
#endif

bigint c++

//bigint.cpp methods implementation
#include <stdexcept>
#include"Bigint.hpp"
#include<algorithm>
/**
//**************************** overloading operator multiplication ********************************************
********************************         Amir Ammar                 *******************************************/
Bigint operator*(const Bigint& a, const Bigint& b){
  Bigint temp1 = a;
  Bigint temp2 = b;
  Bigint temp3;  // using temp3 object as a temporary to store the chars each iteration 
  temp3.m_digits ={'0'};
  Bigint temp4;  // for the arithmetic operation + between (temp3+temp4) and next temp4 to store the value of temp3 
  temp4.m_digits = {'0'};
  Bigint mult;      // the final values will be stored here and we return mult 
  mult.m_digits = {'0'};
  if(temp1.is_zero()||temp2.is_zero()){return mult.m_digits;}  // if one of them is zero we return mult == '0';
  char devide_by_ten{'0'};     // initializing devided by ten variable as a char type
  char devide_by_modulo{'0'};  // initializing devided by modulo variable as a char type 
  int size_of_in {0};          // size of in is a variable that will decide next how many zeroes will be pushed inside temp3 each iteration
  if(temp1.m_digits>temp2.m_digits){  // if statement to in
    size_of_in = temp2.m_digits.size();// i decided to intilize it according to the size of the bigger Bigint.size()
  }else{
    size_of_in = temp1.m_digits.size();
  }
  int push_zeros = size_of_in ; // we need to loop and push zeroes so i need this variable first to have the same value as size_of_in
  int counter = 0; // to increment the counter each time a zero is pushed and finally to break the loop 
  int minus_one = 0; // to decrment the valuee by one each loop
  auto iterator1=temp1.m_digits.end(); 
  auto iterator2=temp2.m_digits.end();
  // auto iterator1_1=temp1.m_digits.end(); // those variables was a part of experiment that succeeded 
  // auto iterator2_2=temp2.m_digits.end();  // those variables was a part of experiment that succeeded 
   while(true)//iterator1_1!=temp1.begin()||iterator2_2!=temp2.begin()
  {
      temp3.m_digits.clear();                              // cleaning the temp3 each loop so we can store the new value 
        while(push_zeros+minus_one+counter != size_of_in){ // while loop to push zero for temp3 each iteration
          ++counter;
          temp3.m_digits.emplace_front('0');
        }
        --minus_one;
        counter =0;
        --iterator2;
         if(iterator2==temp2.m_digits.end())break;  // break when we finally reached the last iteration 
            while(iterator1!=temp1.m_digits.begin()){ 
              --iterator1;
              devide_by_modulo=((*iterator1-48)*(*iterator2-48)+(devide_by_ten-48))%10+'0';
              devide_by_ten = ((*iterator1-'0')*(*iterator2-'0')+(devide_by_ten-'0'))/10+'0';
              temp3.m_digits.emplace_front(devide_by_modulo);
            }
            if(devide_by_ten != '0')temp3.m_digits.emplace_front(devide_by_ten);
            devide_by_modulo = {'0'};
            devide_by_ten ={'0'};
    mult = temp3+temp4; // the arithmetic operation between temp3+temp4 stored inside mult 
    temp4= temp4+temp3;  // the result will be also stored inside temp4 so we can do another + operation but with different values inside temp3
    iterator1=temp1.m_digits.end();// initializing the iterator1 as the end so we could loop again with same values 
    // --iterator2_2; // experiment 
    // --iterator1_1; // experiment 
  }
  if(a.m_is_negative==true&& b.m_is_negative==true){return mult;} // if both negative we return mult with none negative sign 
  if(a.m_is_negative==true||b.m_is_negative==true)mult.m_digits.emplace_front('-'); // if one of them is negative we push - 
  return mult;  // and finally we return mult 
}