mongodb aggregate group
#equivalent of the following SQL instruction:
# SELECT COUNT(*) FROM Table
# GROUP BY your_field
query = db.collection.aggregate([
{
"$group": {
"_id": "$your_field", #GROUP BY your_field
"total": {"$sum":1} #COUNT(*)
}
}
])mongodb aggregate cond $in
cond: {
$and: [{
$in: ['$$viewsDoc.year', [1, 2, 3]]
}]
}MONGODB AGGREGATION tutorials
db.stocks.find().pretty()how to use mongoose aggregate
const agg = Model.aggregate([{ $match: { age: { $gte: 25 } } }]);
for await (const doc of agg) {
console.log(doc.name);
}Copyright © 2021 Codeinu
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