Answers for "sqrt of a number in java"

1

sqrt in java

Math.sqrt(num)
Posted by: Guest on October-05-2021
1

square root of a number in java

Scanner in=new Scanner(System.in);
int num=in.nextInt();
System.out.println(Math.sqrt(num)); // the sqrt function gives a value in 'double' data type.
Posted by: Guest on August-20-2020
0

finding square root geeks'

# THIS METHOD IS CALLED NEWTON-RAPHSON METHOD
n = 23049234
sq =1          # you can take it as any positive number
i = 0
for i in range(n):    
    temp = sq
    sq = (sq + n/sq)/2
    i += 1
    if temp  == sq:  # as the value starts repeating we have reached the final precison
        break
print(sq)
Posted by: Guest on December-25-2020

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