how to check if number is even
if ( n % 2 == 0 ) {
// n is even
}
else {
//otherwise odd
}how to check if number is even
if ( n % 2 == 0 ) {
// n is even
}
else {
//otherwise odd
}Find Numbers with Even Number of Digits
// https://leetcode.com/problems/find-numbers-with-even-number-of-digits/
// Find Numbers with Even Number of Digits
class Solution {
public int findNumbers(int[] nums) {
int evenDigits = 0;
for (int num : nums) {
if (isEvenDigit(num)) evenDigits++;
}
return evenDigits;
}
/*
// counting the number of digits (Method 1)
int digitcount2(int number) {
if (number < 0) number *= -1;
if (number == 0) return 1;
int count = 0;
while (number > 0) {
number /= 10;
count++;
}
return count;
}
*/
// counting the number of digits (Method 2)
int digitcount(int number){
return (int) (Math.log10(number)) + 1;
}
boolean isEvenDigit(int number){
return digitcount(number) % 2 == 0;
}
}Copyright © 2021 Codeinu
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