Answers for "string pattern = "dd-mm-yyyy";"

5

dd.mm.yyyy pattern regex

^([0]?[1-9]|[1|2][0-9]|[3][0|1])[./-]([0]?[1-9]|[1][0-2])[./-]([0-9]{4}|[0-9]{2})$
Posted by: Guest on December-17-2020

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