Answers for "javascript compare 2 object arrays and remove duplicates"

how to remove duplicate array object in javascript

const arr = [{id: 1, name: 'one'}, {id: 2, name: 'two'}, {id: 1, name: 'one'}]

const ids = arr.map(o => o.id)
const filtered = arr.filter(({id}, index) => !ids.includes(id, index + 1))

console.log(filtered)

remove duplicates objects from array javascript

arr.reduce((acc, current) => {
  const x = acc.find(item => item.id === current.id);
  if (!x) {
    return acc.concat([current]);
  } else {
    return acc;
  }
}, []);

javascript remove duplicate objects from array es6

const
    listOfTags = [{ id: 1, label: "Hello", color: "red", sorting: 0 }, { id: 2, label: "World", color: "green", sorting: 1 }, { id: 3, label: "Hello", color: "blue", sorting: 4 }, { id: 4, label: "Sunshine", color: "yellow", sorting: 5 }, { id: 5, label: "Hello", color: "red", sorting: 6 }],
    keys = ['label', 'color'],
    filtered = listOfTags.filter(
        (s => o => 
            (k => !s.has(k) && s.add(k))
            (keys.map(k => o[k]).join('|'))
        )
        (new Set)
    );

console.log(filtered);

combine 2 "arrays with objects" and remove object duplicates javascript

// Join Without Dupes.
const joinWithoutDupes = (A, B) => {
  const a = new Set(A.map(x => x.item))
  const b = new Set(B.map(x => x.item))
  return [...A.filter(x => !b.has(x.item)), ...B.filter(x => !a.has(x.item))]
}

// Proof.
const output = joinWithoutDupes([{item:"apple",description: "lorem"},{item:"peach",description: "impsum"}], [{item:"apple", description: "dolor"},{item:"grape", description: "enum"}])
console.log(output)