Answers for "how to remove duplicate object based on condiotion js"

how to remove duplicate array object in javascript

const arr = [{id: 1, name: 'one'}, {id: 2, name: 'two'}, {id: 1, name: 'one'}]

const ids = arr.map(o => o.id)
const filtered = arr.filter(({id}, index) => !ids.includes(id, index + 1))

console.log(filtered)

remove duplicate objects from array javascript

const addresses = [...]; // Some array I got from async call

const uniqueAddresses = Array.from(new Set(addresses.map(a => a.id)))
 .map(id => {
   return addresses.find(a => a.id === id)
 })

javascript remove duplicate objects from array es6

const
    listOfTags = [{ id: 1, label: "Hello", color: "red", sorting: 0 }, { id: 2, label: "World", color: "green", sorting: 1 }, { id: 3, label: "Hello", color: "blue", sorting: 4 }, { id: 4, label: "Sunshine", color: "yellow", sorting: 5 }, { id: 5, label: "Hello", color: "red", sorting: 6 }],
    keys = ['label', 'color'],
    filtered = listOfTags.filter(
        (s => o => 
            (k => !s.has(k) && s.add(k))
            (keys.map(k => o[k]).join('|'))
        )
        (new Set)
    );

console.log(filtered);

remove duplicates from array of objects javascript

arr.filter((v,i,a)=>a.findIndex(t=>(t.place === v.place && t.name===v.name))===i)

duplicate value removed in array of object in javascript

const arr = [{id: 1, name: 'one', position: 1}, {id: 2, name: 'two', position: 2}, {id: 1, name: 'one', position: 3}]

const ids = arr.map(o => o.id)
const filtered = arr.filter(({id}, index) => !ids.includes(id, index + 1))
console.log(filtered,'filtered')

const uniqueArray = arr.filter((v, i, a) => a.findIndex(t => (t.name === v.name)) == i)
console.log(uniqueArray,'uniqueArray');