javascript reduce
var array = [36, 25, 6, 15];
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82javascript reduce
var array = [36, 25, 6, 15];
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82javascript reduce
You can return whatever you want from reduce method, reduce array method good for computational problems
const arr = [36, 25, 6, 15];
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, 0); // this will return Number
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, []); // this will return array
let {total} = array.reduce(function(accumulator, currentValue) {
let {currentVal} = currentValue
return accumulator + currentVal;
}, {
total: 0
}); // this will return object
And one additional rule is always always retrun the first param, which do arithmetic operations.reduce javascript
let fil = res.map(x=>Object.keys(x).filter(x=>x!='process' && x!='relay_type')
.reduce((a,b)=>{
a[b] = x[b]
return a
},{})).map(x=>Object.assign(x,{total:'wew'}))Copyright © 2021 Codeinu
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