javascript reduce
var array = [36, 25, 6, 15];
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82javascript reduce
var array = [36, 25, 6, 15];
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82syntax of reduce in js
[1,2,3,4,5].reduce((acc, current)=>acc+current, 0)reduce method
The reduce() method executes a reducer function (that you provide) on each element of the array, resulting in single output value.
The reducer function takes four arguments:
Accumulator (acc)
Current Value (cur)
Current Index (idx)
Source Array (src)
//syntax
arr.reduce(callback( accumulator, currentValue, [, index[, array]] )[, initialValue])
//example flatten an array
let flattened = [[0, 1], [2, 3], [4, 5]].reduce(
( accumulator, currentValue ) => accumulator.concat(currentValue),
[]
)javascript reduce
let arr = [1,2,3]
/*
reduce takes in a callback function, which takes in an accumulator
and a currentValue.
accumulator = return value of the previous iteration
currentValue = current value in the array
*/
// So for example, this would return the total sum:
const totalSum = arr.reduce(function(accumulator, currentVal) {
return accumulator + currentVal
}, 0);
> totalSum == 0 + 1 + 2 + 3 == 6
/*
The '0' after the callback is the starting value of whatever is being
accumulated, if omitted it will default to whatever the first value in
the array is, i.e:
> totalSum == 1 + 2 + 3 == 6
if the starting value was set to -1 for ex, the totalSum would be:
> totalSum == -1 + 1 + 2 + 3 == 5
*/
// arr.reduceRight does the same thing, just from right to leftCopyright © 2021 Codeinu
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