how to subtract 48 hours from datetime filed in python without using pandas
from datetime import datetime, timedelta
d = datetime.today() - timedelta(hours=0, minutes=50)
d.strftime('%H:%M %p')how to subtract 48 hours from datetime filed in python without using pandas
from datetime import datetime, timedelta
d = datetime.today() - timedelta(hours=0, minutes=50)
d.strftime('%H:%M %p')pandas subtract days from date
df['date1'] = df['date'] - pd.to_timedelta(df['day'], unit='d')
print (df)
date day date1
0 2015-10-10 23 2015-09-17
1 2015-12-19 9 2015-12-10
2 2016-03-05 34 2016-01-31
3 2016-09-17 23 2016-08-25
4 2016-04-30 2 2016-04-28Copyright © 2021 Codeinu
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