permcheck codility python
def solution(A):
A = sorted(A)
ans = 1
for i in range(0, len(A)):
if A[i] == ans:
ans += 1
else:
break
if ans == len(A)+1:
return 1
return 0
permcheck codility python
def solution(A):
A = sorted(A)
ans = 1
for i in range(0, len(A)):
if A[i] == ans:
ans += 1
else:
break
if ans == len(A)+1:
return 1
return 0
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