Answers for "sort dictionary based on value in descending order python"

0

how to sort a list of dictionary by value in descending order?

1. new_list = sorted(old_list, key=lambda k: k['key'], reverse=True)
/*use reverse=False for ascending order*/
Posted by: Guest on June-22-2020
0

order dictionary by value python

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_dict = {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
print(sorted_dict)
#{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
Posted by: Guest on June-28-2021

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