sum of all multiples of 3 and 5 below 100
c = list(range(1,100))
total = 0
for i in (c):
if i % 3 == 0 or i % 5 == 0:
total += i
print (total)sum of all multiples of 3 and 5 below 100
c = list(range(1,100))
total = 0
for i in (c):
if i % 3 == 0 or i % 5 == 0:
total += i
print (total)sum of multiples of 5 from 1 to 100
total = 0
for i in range(1, 100):
if i % 3 == 0:
total = total + i
print(total)
total1 = 0
for i in range(1, 100):
if i % 5 == 0:
total1 = total1 + i
print(total1)Sum of all the multiples of 3 or 5
const findSum = n => {
let countArr = []
for(let i = 0; i <= n; i++) if(i % 3 === 0 || i % 5 === 0) countArr.push(i)
return countArr.reduce((acc , curr) => acc + curr)
}
console.log(findSum(5))Copyright © 2021 Codeinu
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