Answers for "sort dictionary of listd by value python"

sort list of dictionaries python by value

newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

Posted by: Guest on March-25-2020

sort dict by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Posted by: Guest on April-22-2020

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