count consecutive values in python
#count consecutif 1 in list. list exemple l=['1','1','0','1','0','1,'1',1']
cpt=0
compte=[]
for i in ch:
if i=='1':
cpt +=1
else:
compte.append(cpt)
cpt=0
compte.append(cpt)count consecutive values in python
>>> from itertools import groupby
>>> def groups(l):
... return [sum(g) for i, g in groupby(l) if i == 1]
...
>>> groups([0,1,0,0,0])
[1]
>>> groups([0,0,1,1,0])
[2]
>>> groups([1,1,0,1,1])
[2, 2]how to fill an array with consecutive numbers python
array = [x for x in range(0, 10)]
print(array)
#OUTPUT: [0, 1, 2, 3, 4, 5 6, 7, 8, 9]python consecutive numbers difference between
[y-x for x, y in zip(A[:-1], A[1:])]
>>> A = [1, 10, 100, 50, 40]
>>> [y-x for x, y in zip(A[:-1], A[1:])]
[9, 90, -50, -10]Copyright © 2021 Codeinu
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