Answers for "how to classify a dictionary by ascending value order in python"

1

order dictionary by value python

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_dict = {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
print(sorted_dict)
#{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
Posted by: Guest on June-28-2021
-1

python dictionary print key value ascending order

word_dict = { 'this': 11, 'at': 9, 'here': 5, 'why': 12, 'is': 2 }
# Sort Dictionary by value in descending order using lambda function
sorted_dict = dict( sorted(word_dict.items(),
                           key=lambda item: item[1],
                           reverse=True))
print('Sorted Dictionary: ')
print(sorted_dict)
Posted by: Guest on August-07-2021

Code answers related to "how to classify a dictionary by ascending value order in python"

Python Answers by Framework

Browse Popular Code Answers by Language