binary number in python 32 bit
>>> '{:032b}'.format(100)
'00000000000000000000000001100100'
>>> '{:032b}'.format(8589934591)
'111111111111111111111111111111111'
>>> '{:032b}'.format(8589934591 + 1)
'1000000000000000000000000000000000' # N.B. this is 33 digits longhow to convert binary to integer in python
def binary2int(binary):
int_val, i, n = 0, 0, 0
while(binary != 0):
a = binary % 10
int_val = int_val + a * pow(2, i)
binary = binary//10
i += 1
print(int_val)
binary2int(101)Copyright © 2021 Codeinu
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