count number of zeros in a number python
# credit to Stack Overflow user in source link
>>> def count_zeros(number):
... return str(number).count('0')
...
>>> count_zeros(49690101904335902069)
5count number of zeros in a number python
# credit to Stack Overflow user in source link
>>> def count_zeros(number):
... return str(number).count('0')
...
>>> count_zeros(49690101904335902069)
5Efficiently count zero elements in numpy array?
In [3]: arr
Out[3]:
array([[1, 2, 0, 3],
[3, 9, 0, 4]])
In [4]: np.count_nonzero(arr==0)
Out[4]: 2
In [5]:def func_cnt():
for arr in arrs:
zero_els = np.count_nonzero(arr==0)
# here, it counts the frequency of zeroes actuallyCopyright © 2021 Codeinu
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