django group by
# If you mean to do aggregation you can use the aggregation features of the ORM:
from django.db.models import Count
Members.objects.values('designation').annotate(dcount=Count('designation'))
# This results in a query similar to:
SELECT designation, COUNT(designation) AS dcount
FROM members GROUP BY designation
#and the output would be of the form
[{'designation': 'Salesman', 'dcount': 2},
{'designation': 'Manager', 'dcount': 2}]How to print a groupby object
import pandas as pd
df = pd.DataFrame({'A': ['one', 'one', 'two', 'three', 'three', 'one'], 'B': range(6)})
print(df)
# A B
#0 one 0
#1 one 1
#2 two 2
#3 three 3
#4 three 4
#5 one 5
grouped_df = df.groupby('A')
for key, item in grouped_df:
print(grouped_df.get_group(key), "nn")
# A B
#A
#one 0 one 0
# 1 one 1
# 5 one 5
#two 2 two 2
#three 3 three 3
# 4 three 4Copyright © 2021 Codeinu
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