Answers for "simple http server python linux curl"

1

python run curl

import shlex
cmd = '''curl -X POST -d  '{"nw_src": "10.0.0.1/32", "nw_dst": "10.0.0.2/32", "nw_proto": "ICMP", "actions": "ALLOW", "priority": "10"}' http://localhost:8080/firewall/rules/0000000000000001'''
args = shlex.split(cmd)
process = subprocess.Popen(args, shell=False, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
stdout, stderr = process.communicate()
Posted by: Guest on June-26-2020
0

curl to python

import requests

headers = {
    'PRIVATE-TOKEN': '<your_access_token>',
}

response = requests.get('https://gitlab.example.com/api/v4/projects/:id/access_requests', headers=headers)
Posted by: Guest on November-11-2021

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