numpy find rows containing nan
# in each case returns array of bool
np.isnan(a).any(axis=1) # rows where any value is nan
np.isnan(a).all(axis=1) # rows where all values are nannumpy find rows containing nan
# in each case returns array of bool
np.isnan(a).any(axis=1) # rows where any value is nan
np.isnan(a).all(axis=1) # rows where all values are nanpython numpy array replace nan with string
import numpy as np
l=['foo', 'bar', 'baz', np.nan]
l_new=['missing' if x is np.nan else x for x in l]
print l_new
# Result:
# ['foo', 'bar', 'baz', 'missing']Copyright © 2021 Codeinu
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