Answers for "4 nested for loops"

nested loop

for a in range(1,3):
    if a%2!=0:
        print(a,end=" ")
        
    for b in range(1,a+1):
        if b%5==0:
         print(b,end=" ")
         
        for c in range(a,b+1):
            if c%3!=0:
             print(c,end=" ")

    print()

nested loop

def something(a):
    for methodname in ['method1', 'method2', 'method3']:
        try:
            m = getattr(a, methodname)
        except AttributeError:
            pass
        else:
            return m()
    raise AttributeError

nested for loop

//nested for
for (expr1; expr2; expr3) {
    for (expr1; expr2; expr3) {
        //statement;
    }
}

// EXAMPLE
for ($i = 1; $i < 5; $i++) {
    for ($j = 1; $j <= $i; $j++) {
        echo " * ";
    }
    echo '<br />';
}