Answers for "return unique values in an array python"

find all unique items in dictionary value python

L = [{"V":"S001"}, {"V": "S002"}, {"VI": "S001"}, {"VI": "S005"}, {"VII":"S005"}, {"V":"S009"},{"VIII":"S007"}]
print("Original List: ",L)
u_value = set( val for dic in L for val in dic.values())
print("Unique Values: ",u_value)

return position of a unique value in python array

In [304]: array = np.array([1, 1, 2, 3, 2, 1, 2, 3])

In [305]: np.unique(array)            # unique values in `array`
Out[305]: array([1, 2, 3])

In [306]: array == 1                  # retrieve a boolean mask where elements are equal to 1
Out[306]: array([ True,  True, False, False, False,  True, False, False])

In [307]: (array == 1).nonzero()[0]   # get the `True` indices for the operation above
Out[307]: array([0, 1, 5])

count unique values in python

aa="XXYYYSBAA"
bb=dict(zip(list(aa),[list(aa).count(i) for i in list(aa)]))
print(bb)
# output:
# {'X': 2, 'Y': 3, 'S': 1, 'B': 1, 'A': 2}