add bash command
a=`expr "$a" + "$num"`
a=$(($a+$num))
((a=a+num))
let a=a+num
((a+=num))add bash command
a=`expr "$a" + "$num"`
a=$(($a+$num))
((a=a+num))
let a=a+num
((a+=num))bash calculate sum
#Just use following structure for summing up varibles:
sum=$((var1 + var2))
#For float numbers use next instruction:
sum=$(bc <<< $var1'+'$var2)Copyright © 2021 Codeinu
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