Answers for "how to filter a jquery list"

0

jq filter array

$ json='[{"genre":"deep house"}, {"genre": "progressive house"}, {"genre": "dubstep"}]'
$ echo "$json" | jq -c '.[] | select(.genre | contains("house"))'
{"genre":"deep house"}
{"genre":"progressive house"}
Posted by: Guest on June-26-2020
0

filtering jquery

$("span strong").first();   // first strong in first span
$("span strong").last();    // last strong in last span
$("div").eq(9);             // element with a specific index
$("div").filter(".big");    // all div elements with .big class
$("div").not(".big");       // opposite of filter
Posted by: Guest on August-05-2021

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