Answers for "url as urlrequest swift"

Swift

0

swift url request

import Foundation

let apiUrl = URL(string: "https://api.chucknorris.io/jokes/random")!
let dataTask = URLSession.shared.dataTask(with: apiUrl) { (data, response, error) in
    guard let data = data, error == nil else {
        print("no data")
    }
    let jsonResult = try! JSONSerialization.jsonObject(with: data, options: []) as! [String: Any]
    print(jsonResult["value"])
}
dataTask.resume()

Posted by: Guest on May-22-2021

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