Answers for "js includes string array"

3

js check if string includes from array

wordsArray = ['hello', 'to', 'nice', 'day']
yourString = 'Hello. Today is a nice day'.toLowerCase()
result = wordsArray.every(w => yourString.includes(w))
console.log('result:', result)
Posted by: Guest on October-13-2021
1

js check if string includes from array

const found = arrayOfStrings.find(v => str.includes(v));
Posted by: Guest on October-13-2021
0

js check if string includes from array

function buildSearch(substrings) {
  return new RegExp(
    substrings
    .map(function (s) {return s.replace(/[.*+?^${}()|[]\]/g, '\$&');})
    .join('{1,}|') + '{1,}'
  );
}


var pattern = buildSearch(['hello','world']);

console.log(pattern.test('hello there'));
console.log(pattern.test('what a wonderful world'));
console.log(pattern.test('my name is ...'));
Posted by: Guest on October-14-2021
0

if array includes string

function droids(arr) {
  let result = 'These are not the droids you're looking for';
  for(let i=0; i<arr.length;i++) {
      if (arr[i] === 'Droids') {
      result = 'Found Droid';
    }
  }
  return result;
}

// Uncomment these to check your work! 
const starWars = ["Luke", "Finn", "Rey", "Kylo", "Droids"]
const thrones = ["Jon", "Danny", "Tyrion", "The Mountain", "Cersei"]
console.log(droids(starWars)) // should log: "Found Droids!"
console.log(droids(thrones)) // should log: "These are not the droi





//A simpler approach 

console.log(starWars.includes('Droids') ? 'Droid Found' : 'These are not the droids you're looking for');
console.log(thrones.includes('Droids') ? 'Droid Found' : 'These are not the droids you're looking for');
Posted by: Guest on September-19-2021
0

js array string includes

if (new RegExp(substrings.join("|")).test(string)) {
    // At least one match
}
Posted by: Guest on July-15-2021

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