Answers for "typescript correct way to type object from promise"

1

typescript get the promise return type

type AsyncReturnType<T extends (...args: any) => any> =
	T extends (...args: any) => Promise<infer U> ? U :
	T extends (...args: any) => infer U ? U :
	any
Posted by: Guest on June-14-2021
0

typescript get type from promise

function promiseOne() {
  return Promise.resolve(1)
}
    
const promisedOne = promiseOne()
    
// note PromiseLike instead of Promise, this lets it work on any thenable
type ThenArg<T> = T extends PromiseLike<infer U> ? U : T
    
type PromiseOneThenArg = ThenArg<typeof promisedOne> // => number
// or
type PromiseOneThenArg2 = ThenArg<ReturnType<typeof promiseOne>> // => number
Posted by: Guest on May-27-2021

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