Answers for "typescript infer type"

1

contextual typing in typescript

Lets say you defined a call signature for any function.

type greet = (name: string) => void 

Now, when you declare any function having this type, like this

const sayHello: greet = (name) =>{
  console.log("hello ", name);
}

you dont need to explicitly annotate funciton paramters and return type,
  this is called "CONTEXTUAL TYPING".
Posted by: Guest on October-14-2020
0

Include Type TypeScript

// type a = Equal<'a' | 'a'>
type Equal<T, K> = K extends T ? true : false;
type Includes<T extends any[], K> = T extends [infer first, ...infer Rest]
	? Equal<first, K> extends true
		? true
		: Includes<Rest, K>
	: false;
type isPillarMen = Includes<['Kars', 'Esidisi', 'Wamuu', 'Santana'], 'Kars'>; // expected to be `false`
Posted by: Guest on May-28-2022
0

typescript different types support

function getLength(obj: string | string[]) {
  return obj.length;
}
Posted by: Guest on March-18-2022

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