c# open file dialog
OpenFileDialog dialog = new OpenFileDialog();
if (DialogResult.OK == dialog.ShowDialog())
{
string path = dialog.FileName;
}c# open file dialog
OpenFileDialog dialog = new OpenFileDialog();
if (DialogResult.OK == dialog.ShowDialog())
{
string path = dialog.FileName;
}open file dialog in vb.net
'How to open the file path in Visual Basic
OpenFileDialog1.Filter = "TEXT FILE | *.txt |PDF FILE |.pdf |ALL FILES |*.*"
If OpenFileDialog1.ShowDialog = DialogResult.OK Then
For x = 0 To OpenFileDialog1.FileNames.Count - 1
MsgBox(OpenFileDialog1.FileNames(x))
Next
End IfCopyright © 2021 Codeinu
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