vba >>>
'Many programming languages have a bitwise zero-fill right-shift operator: >>>
'VBA does not. However, it can be emulated in a performant function:
Public Function ShiftRightZeroFill&(ByVal n&, Optional ByVal shifts& = 1)
Dim d&
If shifts = 0 Then ShiftRightZeroFill = n: Exit Function
If n And &H80000000 Then
shifts = shifts - 1
n = (n And &H7FFFFFFF) 2 Or &H40000000
End If
Select Case shifts
Case 0: d = n
Case 1: d = n 2&
Case 2: d = n 4&
Case 3: d = n 8&
Case 4: d = n 16&
Case 5: d = n 32&
Case 6: d = n 64&
Case 7: d = n 128&
Case 8: d = n 256&
Case 9: d = n 512&
Case 10: d = n 1024&
Case 11: d = n 2048&
Case 12: d = n 4096&
Case 13: d = n 8192&
Case 14: d = n 16384&
Case 15: d = n 32768
Case 16: d = n 65536
Case 17: d = n 262144
Case 18: d = n 262144
Case 19: d = n 524288
Case 20: d = n 1048576
Case 21: d = n 2097152
Case 22: d = n 4194304
Case 23: d = n 8388608
Case 24: d = n 16777216
Case 25: d = n 33554432
Case 26: d = n 67108864
Case 27: d = n 134217728
Case 28: d = n 268435456
Case 29: d = n 536870912
Case 30: d = n 1073741824
Case 31: d = &H0&
End Select
ShiftRightZeroFill = d
End Function
'----------------------------------------------------------------------------
'Don't be off-put at the size of the function. This is many times faster than
'any other VBA function that carries out bitwise zero-filled -right-shfits.
'The hard-coded values are much faster than calculating with exponentiation.
MsgBox ShiftRightZeroFill&(-9, 2) <--displays: 1073741821
'NB: Remember that VBA Longs are signed.