length of a char array in c
char chararray[10];
size_t len = strlen(chararray);
length of a char array in c
char chararray[10];
size_t len = strlen(chararray);
c++ length of char*
#include <iostream>
#include <string.h>
using namespace std;
int main()
{
char *str = "ABC";
cout << strlen(str) << endl;
return 0;
}
how to find length of character array in c++
#include <iostream>
using namespace std;
int main()
{
char arr[] = "grepper";
cout << sizeof(arr) << endl;
return 0;
// keep it in mind that character arrays have length of one more than your characters because last one is for \0 to show that word has ended
}
c++ length of char array
char* example = "Lorem ipsum dolor sit amet";
int length = strlen(example);
std::cout << length << '\n'; // 26
char size length c++
char* a = "ABC";
int length = sizeof(a)/sizeof(char);
how to find the size of a character array in c++
Instead of sizeof() for finding the length of strings or character
arrays, just use strlen(string_name) with the header file
#include <cstring>
it's easier.
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