poiner in c
#include <stdio.h>
int main() {
int c = 5;
int *p = &c;
printf("%d", *p); // 5
return 0;
}poiner in c
#include <stdio.h>
int main() {
int c = 5;
int *p = &c;
printf("%d", *p); // 5
return 0;
}poiner in c
int c, *pc;
// pc is address but c is not
pc = c; // Error
// &c is address but *pc is not
*pc = &c; // Error
// both &c and pc are addresses
pc = &c;
// both c and *pc values
*pc = c;poiner in c
#include <stdio.h>
int main()
{
int var =10;
int *p;
p= &var;
printf ( "Address of var is: %p", &var);
printf ( "\nAddress of var is: %p", p);
printf ( "\nValue of var is: %d", var);
printf ( "\nValue of var is: %d", *p);
printf ( "\nValue of var is: %d", *( &var));
/* Note I have used %p for p's value as it represents an address*/
printf( "\nValue of pointer p is: %p", p);
printf ( "\nAddress of pointer p is: %p", &p);
return 0;
}Copyright © 2021 Codeinu
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