poiner in c
int* pc, c, d;
c = 5;
d = -15;
pc = &c; printf("%d", *pc); // Output: 5
pc = &d; printf("%d", *pc); // Ouptut: -15poiner in c
int* pc, c, d;
c = 5;
d = -15;
pc = &c; printf("%d", *pc); // Output: 5
pc = &d; printf("%d", *pc); // Ouptut: -15poiner in c
int c, *pc;
// pc is address but c is not
pc = c; // Error
// &c is address but *pc is not
*pc = &c; // Error
// both &c and pc are addresses
pc = &c;
// both c and *pc values
*pc = c;how to make pointers in c
datatype *var;
variable var actually holds the address of the data(memory where it is stored)
*var lets you access the data stored at that addresspointer to an address
#include <stdio.h>
int main()
{
/* Pointer of integer type, this can hold the
* address of a integer type variable.
*/
int *p;
int var = 10;
/* Assigning the address of variable var to the pointer
* p. The p can hold the address of var because var is
* an integer type variable.
*/
p= &var;
printf("Value of variable var is: %d", var);
printf("\nValue of variable var is: %d", *p);
printf("\nAddress of variable var is: %p", &var);
printf("\nAddress of variable var is: %p", p);
printf("\nAddress of pointer p is: %p", &p);
return 0;
}Copyright © 2021 Codeinu
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