size of an array c
int a[20];
int length;
length = sizeof(a) / sizeof(int);size of an array c
int a[20];
int length;
length = sizeof(a) / sizeof(int);how to dynamically allocate array size in c
// declare a pointer variable to point to allocated heap space
int *p_array;
double *d_array;
// call malloc to allocate that appropriate number of bytes for the array
p_array = (int *)malloc(sizeof(int)*50); // allocate 50 ints
d_array = (int *)malloc(sizeof(double)*100); // allocate 100 doubles
// use [] notation to access array buckets
// (THIS IS THE PREFERED WAY TO DO IT)
for(i=0; i < 50; i++) {
p_array[i] = 0;
}
// you can use pointer arithmetic (but in general don't)
double *dptr = d_array; // the value of d_array is equivalent to &(d_array[0])
for(i=0; i < 50; i++) {
*dptr = 0;
dptr++;
}Copyright © 2021 Codeinu
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