size of an array c
int a[20];
int length;
length = sizeof(a) / sizeof(int);size of an array c
int a[20];
int length;
length = sizeof(a) / sizeof(int);find length of array in c
int a[17]; // initializing an array
int length = sizeof(a)/sizeof(a[0]); // divide array size(in byte)/ size of the first element of the array of the same type, here int(integer size is 4byte)passing the length of an int array c
//I suggest using strlen (of #include<string.h>)
//if you want only the size of the occupied index
int prices[5] = { 1, 2, 3, 4, 5 };
int size = strlen(prices);
printf("%d", size); // 5Copyright © 2021 Codeinu
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