array length in c++
int a[20];
int length;
length = sizeof(a) / sizeof(int);array length in c++
int a[20];
int length;
length = sizeof(a) / sizeof(int);array length c++
#include <iostream>
using namespace std;
#define size(type) ((char *)(&type+1)-(char*)(&type))
int main(){
int arr[5] = {1, 2, 3, 4, 5};
cout << size(arr) / size(arr[0]) << endl; //returns 5
//alternatively
cout << sizeof(arr) / sizeof(int) << endl; //returns 5
}find length of array c++
#include <iostream>
using namespace std;
int main() {
int arr[5] = {4, 1, 8, 2, 9};
int len = sizeof(arr)/sizeof(arr[0]);
cout << "The length of the array is: " << len;
return 0;
}array length c++
// array::size
#include <iostream>
#include <array>
int main ()
{
std::array<int,5> myints;
std::cout << "size of myints: " << myints.size() << std::endl;
std::cout << "sizeof(myints): " << sizeof(myints) << std::endl;
return 0;
}c++ array with variable size
int n = 10;
double* a = new double[n]; // Don't forget to delete [] a; when you're done!Copyright © 2021 Codeinu
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