leap year algorithm
def isLeapYear (year):
if ((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0):
true
else:
falseleap year algorithm
def isLeapYear (year):
if ((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0):
true
else:
falseleap year c program
#include <stdio.h>
int main() {
int year;
printf("Enter a year: ");
scanf("%d", &year);
// leap year if perfectly visible by 400
if (year % 400 == 0) {
printf("%d is a leap year.", year);
}
// not a leap year if visible by 100
// but not divisible by 400
else if (year % 100 == 0) {
printf("%d is not a leap year.", year);
}
// leap year if not divisible by 100
// but divisible by 4
else if (year % 4 == 0) {
printf("%d is a leap year.", year);
}
// all other years are not leap year
else {
printf("%d is not a leap year.", year);
}
return 0;
}leap year
const leapYear = (year) => {
if (year % 4 === 0 || year % 400 === 0 && year % 100 !== 0) {
return `${year } : is a leap year`
} else {
return `${year} : is not a leap year`
}
}leap year
import calendar
def is_leap(year):
return calendar.isleap(year)Leap year program
#include <stdio.h>
int main() {
int year;
year = 2016;
if (((year % 4 == 0) && (year % 100!= 0)) || (year%400 == 0))
printf("%d is a leap year", year);
else
printf("%d is not a leap year", year);
return 0;
}Copyright © 2021 Codeinu
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