python 1d array into 2d array
arr2d = [[arr1d[i+j*width] for i in range(width)] for j in range(height)]python 1d array into 2d array
arr2d = [[arr1d[i+j*width] for i in range(width)] for j in range(height)]2d to 1d array python
import numpy as np
ini_array1 = np.array([[1, 2, 3], [2, 4, 5], [1, 2, 3]])
result = ini_array1.flatten()numpy convert 1d array to 2d
import numpy as np
# 1D array
one_dim_arr = np.array([1, 2, 3, 4, 5, 6])
# to convert to 2D array
# we can use the np.ndarray.reshape(shape) function
# here shape is given by two integers seperated by a comma
# the two integers specify m,n for the new matrix
# ensure that the matrix that you are trying to generate
# has a size that meets the number of elements in the 1D array.
# for that make sure that
# m * n = number of elements in the one dimentional array
two_dim_arr = one_dim_arr.reshape(1, 6)
#which returns a 2D array
print(two_dim_arr)
# confirmed by the array.ndim attribute
print(two_dim_arr.ndim)
# you can even specify one of the dimensions as unknown by passing -1
# numpy will infer the length using the array and remaining dimensions
two_dim_arr = one_dim_arr.reshape(1,-1)array 2d to 1d
int array[width * height];
int SetElement(int row, int col, int value)
{
array[width * row + col] = value;
}c program to represent 2d matrix in 1d matrix
#include<stdio.h>
#define n 3
int main()
{
int a[n][n],b[n*n],c[n*n],i,j,k=0,l=0;
printf(“\n Enter elements of 2D array : “);
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
scanf(“%d”,&a[i][j]);
}
}
printf(“\n Given 2D array : \n“);
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
printf(“%d ”,a[i][j]);
}
printf(“\n”);
}
printf(“\n Row wise \n”);
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
b[k]=a[i][j];
k++;
}
}
printf(“\n Column wise \n”);
for(i=0;i<n;i++)
{
for(j=0;j<n;j++)
{
c[l]=a[j][i];
l++;
}
}
}Copyright © 2021 Codeinu
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