size of an array c
int a[20];
int length;
length = sizeof(a) / sizeof(int);size of an array c
int a[20];
int length;
length = sizeof(a) / sizeof(int);array length c
int prices[5] = { 1, 2, 3, 4, 5 };
int size = sizeof prices / sizeof prices[0];
printf("%u", size); /* 5 */c how to find size of array
int a[17];
size_t n = sizeof(a)/sizeof(a[0]);get length of array in c
int a[17];
size_t n = sizeof(a)/sizeof(a[0]);size of an array c
int a[]= { 1, 2, 3, 4, 5, 6, 7 };
int length = sizeof(a) / sizeof(a[0]); //return 7increase size of array in c
#include <stdio.h>#include <stdlib.h>int main(){//a pointer to dynamically allocated memory from the heap is returned. int *a = (int *) malloc(20 * sizeof(int));for(int i = 0; i < 20; i++)a[i] = i + 1;printf("\nThe contents of the array are: \n");for(int i = 0; i < 20; i++)printf("%d\t", a[i]);realloc(a, 40);for(intCopyright © 2021 Codeinu
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