Answers for "C program to print whether a year is leap or not"

C
3

leap year c program

#include <stdio.h>
int main() {
   int year;
   printf("Enter a year: ");
   scanf("%d", &year);

   // leap year if perfectly visible by 400
   if (year % 400 == 0) {
      printf("%d is a leap year.", year);
   }
   // not a leap year if visible by 100
   // but not divisible by 400
   else if (year % 100 == 0) {
      printf("%d is not a leap year.", year);
   }
   // leap year if not divisible by 100
   // but divisible by 4
   else if (year % 4 == 0) {
      printf("%d is a leap year.", year);
   }
   // all other years are not leap year
   else {
      printf("%d is not a leap year.", year);
   }

   return 0;
}
Posted by: Guest on November-20-2020
0

C program to print whether a year is leap or not

#include <stdio.h>
int main() 
{
int year;
printf("Enter the year");
scanf("%d", &year);
if (year % 400 == 0) 
{
printf("%d is a leap year", year);
}
else if (year % 100 == 0) 
{
printf("%d is not leap year", year);
}
else if (year % 4 == 0)
{
printf("%d is a leap year", year);
}
else
{
printf("%d is not leap year", year);
}
return 0;
}
Posted by: Guest on June-24-2021
0

leap year in c

#include <stdio.h>
int main() {
   int year;
   printf("Enter a year: ");
   scanf("%d", &year);

   // leap year if perfectly divisible by 400
   if (year % 400 == 0) {
      printf("%d is a leap year.", year);
   }
   // not a leap year if divisible by 100
   // but not divisible by 400
   else if (year % 100 == 0) {
      printf("%d is not a leap year.", year);
   }
   // leap year if not divisible by 100
   // but divisible by 4
   else if (year % 4 == 0) {
      printf("%d is a leap year.", year);
   }
   // all other years are not leap years
   else {
      printf("%d is not a leap year.", year);
   }

   return 0;
}
Posted by: Guest on June-03-2021

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