Answers for "realloc in c"

c realloc

/*prototype of realloc*/
void *realloc(void *ptr, size_t newsize);

/*use*/
dyn_array = realloc(dyn_array, (dyn_array_size + 1) * sizeof(int));

/*
	adds one more space to dyn_array
    you need stdlib.h for this
*/

realloc

int ptr_new = *realloc(void *ptr, size_t size); 
Where 'ptr_new' is the new pointer you want to point to the required Dynamic
memory, 'ptr' is the already existing pointer to a dynamic memory and 'size'
is the new size of dynamic memory that you want to allocate.

Working:
Realloc creates/allocates a new memory in heap with specified size and copies
all the contents from the previous memory pointer to by the pointer 'ptr'.
It the deallocates the memory in heap pointed to by the old pointer i.e, 'ptr'.
Note: pointer 'ptr' should also point to a memory in heap.

realloc in c

void *realloc(void *ptr, size_t size)

realloc in c

#include <stdio.h>
int main () {
   char *ptr;
   ptr = (char *) malloc(10);
   strcpy(ptr, "Programming");
   printf(" %s,  Address = %u\n", ptr, ptr);

   ptr = (char *) realloc(ptr, 20); //ptr is reallocated with new size
   strcat(ptr, " In 'C'");
   printf(" %s,  Address = %u\n", ptr, ptr);
   free(ptr);
   return 0;
}