using switch case in c
switch (n)
{
case 1: // code to be executed if n = 1;
break;
case 2: // code to be executed if n = 2;
break;
default: // code to be executed if n doesn't match any cases
}using switch case in c
switch (n)
{
case 1: // code to be executed if n = 1;
break;
case 2: // code to be executed if n = 2;
break;
default: // code to be executed if n doesn't match any cases
}switch statement in c
#include <stdio.h>
int main(void)
{
int a = 0;
switch(a)
{
case 1 :
statement("a = 1");
break;
case 2 :
printf("a = 2");
break;
default :
printf("a is neither 1 or 2");
break;
}
}switch case c
switch (expression) {
case constant1:
// statements
break;
case constant2:
// statements
break;
default:
// default statements
}c switch
int i;
switch (i){
case 1:
//The Proccess you want to be executed
break;
case 2:
//The Proccess you want to be executed
break;
default:
break;
}switch case in c
// example of switch case statement
#include <stdio.h>
int main() {
char operator;
double n1, n2;
printf("Enter an operator (+, -, *, /): ");
scanf("%c", &operator);
printf("Enter two operands: ");
scanf("%lf %lf",&n1, &n2);
switch(operator)
{
case '+':
printf("%.1lf + %.1lf = %.1lf",n1, n2, n1+n2);
break;
case '-':
printf("%.1lf - %.1lf = %.1lf",n1, n2, n1-n2);
break;
case '*':
printf("%.1lf * %.1lf = %.1lf",n1, n2, n1*n2);
break;
case '/':
printf("%.1lf / %.1lf = %.1lf",n1, n2, n1/n2);
break;
// operator doesn't match any case constant +, -, *, /
default:
printf("Error! operator is not correct");
}
return 0;
}C switch
Switch(integer-expression)
{
Case c1:
Code;
Case c2: //c1,c2,c3 are constants
Code; //Code is any valid C code
Case c3:
Code;
default:
Code;
}Copyright © 2021 Codeinu
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